JEE MAIN - Mathematics Hindi (2023 - 13th April Morning Shift - No. 8)
$$\int\limits_0^\infty {{6 \over {{e^{3x}} + 6{e^{2x}} + 11{e^x} + 6}}dx = } $$
$${\log _e}\left( {{{256} \over {81}}} \right)$$
$${\log _e}\left( {{{64} \over {27}}} \right)$$
$${\log _e}\left( {{{32} \over {27}}} \right)$$
$${\log _e}\left( {{{512} \over {81}}} \right)$$
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