JEE MAIN - Mathematics Hindi (2023 - 12th April Morning Shift - No. 10)

यदि फलन $$f(x)=\left(\frac{\sqrt{3 e}}{2 \sin x}\right)^{\sin ^2 x}, x \in\left(0, \frac{\pi}{2}\right)$$, का स्थानीय उच्चतम मान $$\frac{k}{e}$$ है, तो $$\left(\frac{k}{e}\right)^8+\frac{k^8}{e^5}+k^8$$ बराबर है:
$$e^3+e^6+e^{10}$$
$$e^3+e^5+e^{11}$$
$$e^3+e^6+e^{11}$$
$$e^5+e^6+e^{11}$$

Comments (0)

Advertisement