JEE MAIN - Mathematics Hindi (2023 - 11th April Evening Shift - No. 8)
यदि $$\left|\begin{array}{ccc}x+1 & x & x \\ x & x+\lambda & x \\ x & x & x+\lambda^2\end{array}\right|=\frac{9}{8}(103 x+81)$$ है, तो $$\lambda, \frac{\lambda}{3}$$ किस समीकरण के मूल हैं?
$$4 x^2+24 x-27=0$$
$$4 x^2-24 x+27=0$$
$$4 x^2-24 x-27=0$$
$$4 x^2+24 x+27=0$$
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