JEE MAIN - Mathematics Hindi (2022 - 30th June Morning Shift - No. 1)
यदि $$S_1 = \left\{ x \in \mathbb{R} - \{ 1,2\} :\frac{(x + 2)(x^2 + 3x + 5)}{ - 2 + 3x - x^2} \geq 0 \right\}$$ और $$S_2 = \left\{ x \in \mathbb{R}:3^{2x} - 3^{x + 1} - 3^{x + 2} + 27 \leq 0 \right\}$$ हो, तो $$S_1 \cup S_2$$ का मान है :
$$( - \infty , - 2] \cup (1,2)$$
$$( - \infty , - 2] \cup [1,2]$$
$$( - 2,1] \cup [2,\infty )$$
$$( - \infty ,2]$$
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