JEE MAIN - Mathematics Hindi (2022 - 29th June Evening Shift - No. 6)
यदि अवकल समीकरण $$\left( {1 + {e^{2x}}} \right){{dy} \over {dx}} + 2\left( {1 + {y^2}} \right){e^x} = 0$$, y (0) = 0, का हल y = y(x) है, तो $$6\left( {y'(0) + {{\left( {y\left( {{{\log }_e}\sqrt 3 } \right)} \right)}^2}} \right)$$ बराबर है -
2
$$-$$2
$$-$$4
$$-$$1
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