JEE MAIN - Mathematics Hindi (2022 - 28th July Morning Shift - No. 9)
यदि अवकल समीकरण
$$\left(\sin ^{2} 2 x\right) \frac{\mathrm{d} y}{\mathrm{~d} x}+\left(8 \sin ^{2} 2 x+2 \sin 4 x\right) y=2 \mathrm{e}^{-4 x}(2 \sin 2 x+\cos 2 x), x \in(0, \pi / 2), y(\pi / 4)=\mathrm{e}^{-\pi}$$
का हल वक्र $$y=y(x)$$ है, तो $$y(\pi / 6)$$ बराबर है :
$$
\frac{2}{\sqrt{3}} e^{-2 \pi / 3}
$$
$$
\frac{2}{\sqrt{3}} e^{2 \pi / 3}
$$
$$
\frac{1}{\sqrt{3}} e^{-2 \pi / 3}
$$
$$
\frac{1}{\sqrt{3}} e^{2 \pi / 3}
$$
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