JEE MAIN - Mathematics Hindi (2022 - 27th June Evening Shift - No. 4)
माना $$\left(0, \frac{\pi}{2}\right)$$ में $$f$$ एक अवकलनीय फलन है । यदि $$\int_{\cos x}^{1} t^{2} f(t) d t=\sin ^{3} x+\cos x$$ है, तो $$\frac{1}{\sqrt{3}} f^{\prime}\left(\frac{1}{\sqrt{3}}\right)$$ बराबर है-
$$6-9 \sqrt{2}$$
$$6-\frac{9}{\sqrt{2}}$$
$$\frac{9}{2}-6 \sqrt{2}$$
$$
\frac{9}{\sqrt{2}}-6
$$
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