JEE MAIN - Mathematics Hindi (2022 - 26th June Morning Shift - No. 5)
$$
\lim\limits_{x \rightarrow \frac{1}{\sqrt{2}}} \frac{\sin \left(\cos ^{-1} x\right)-x}{1-\tan \left(\cos ^{-1} x\right)}$$ बराबर है :
$$\sqrt{2}$$
$$-\sqrt{2}$$
$$\frac{1}{\sqrt{2}}$$
$$-\frac{1}{\sqrt{2}}$$
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