JEE MAIN - Mathematics Hindi (2022 - 26th July Evening Shift - No. 12)
यदि $$0 < x < \frac{1}{\sqrt{2}}$$ तथा $$\frac{\sin ^{-1} x}{\alpha}=\frac{\cos ^{-1} x}{\beta}$$ हैं, तो $$\sin \left(\frac{2 \pi \alpha}{\alpha+\beta}\right)$$ का एक मान है
$$4 \sqrt{\left(1-x^{2}\right)}\left(1-2 x^{2}\right)$$
$$4 x \sqrt{\left(1-x^{2}\right)}\left(1-2 x^{2}\right)$$
$$2 x \sqrt{\left(1-x^{2}\right)}\left(1-4 x^{2}\right)$$
$$4 \sqrt{\left(1-x^{2}\right)}\left(1-4 x^{2}\right)$$
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