JEE MAIN - Mathematics Hindi (2022 - 25th June Evening Shift - No. 5)

$$\lim _{x \rightarrow \frac{\pi}{2}}\left(\tan ^{2} x\left(\left(2 \sin ^{2} x+3 \sin x+4\right)^{\frac{1}{2}}-\left(\sin ^{2} x+6 \sin x+2\right)^{\frac{1}{2}}\right)\right)$$ बराबर है-
$$\frac{1}{12}$$
$$-$$$$\frac{1}{18}$$
$$-$$$$\frac{1}{12}$$
$$\frac{1}{6}$$

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