JEE MAIN - Mathematics Hindi (2022 - 25th July Morning Shift - No. 11)
अवकल समीकरण $$\left(x-y^{2}\right) \mathrm{d} x+y\left(5 x+y^{2}\right) \mathrm{d} y=0$$ का व्यापक हल है :
$$\left(y^{2}+x\right)^{4}=C\left|\left(y^{2}+2 x\right)^{3}\right|$$
$$\left(y^{2}+2 x\right)^{4}=C\left|\left(y^{2}+x\right)^{3}\right|$$
$$\left|\left(y^{2}+x\right)^{3}\right|=C\left(2 y^{2}+x\right)^{4}$$
$$\left|\left(y^{2}+2 x\right)^{3}\right|=C\left(2 y^{2}+x\right)^{4}$$
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