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JEE MAIN - Mathematics Hindi (2021 - 31st August Morning Shift - No. 13)
यदि $${{dy} \over {dx}} = {{{2^{x + y}} - {2^x}} \over {{2^y}}}$$, y(0) = 1, तो y(1) के बराबर होगा :
log
2
(2 + e)
log
2
(1 + e)
log
2
(2e)
log
2
(1 + e
2
)
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