JEE MAIN - Mathematics Hindi (2021 - 31st August Evening Shift - No. 7)
यदि $${{dy} \over {dx}} = {{{2^x}y + {2^y}{{.2}^x}} \over {{2^x} + {2^{x + y}}{{\log }_e}2}}$$, y(0) = 0, तो y = 1 के लिए x का मान अंतराल में है :
(1, 2)
$$\left( {{1 \over 2},1} \right]$$
(2, 3)
$$\left( {0,{1 \over 2}} \right]$$
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