JEE MAIN - Mathematics Hindi (2021 - 31st August Evening Shift - No. 2)
फ़ंक्शन का डोमेन
$$f(x) = {\sin ^{ - 1}}\left( {{{3{x^2} + x - 1} \over {{{(x - 1)}^2}}}} \right) + {\cos ^{ - 1}}\left( {{{x - 1} \over {x + 1}}} \right)$$ है:
$$f(x) = {\sin ^{ - 1}}\left( {{{3{x^2} + x - 1} \over {{{(x - 1)}^2}}}} \right) + {\cos ^{ - 1}}\left( {{{x - 1} \over {x + 1}}} \right)$$ है:
$$\left[ {0,{1 \over 4}} \right]$$
$$[ - 2,0] \cup \left[ {{1 \over 4},{1 \over 2}} \right]$$
$$\left[ {{1 \over 4},{1 \over 2}} \right] \cup \{ 0\} $$
$$\left[ {0,{1 \over 2}} \right]$$
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