JEE MAIN - Mathematics Hindi (2021 - 27th August Morning Shift - No. 2)
यदि $${({\sin ^{ - 1}}x)^2} - {({\cos ^{ - 1}}x)^2} = a$$; 0 < x < 1, a $$\ne$$ 0, तो 2x2 $$-$$ 1 का मान है :
$$\cos \left( {{{4a} \over \pi }} \right)$$
$$\sin \left( {{{2a} \over \pi }} \right)$$
$$\cos \left( {{{2a} \over \pi }} \right)$$
$$\sin \left( {{{4a} \over \pi }} \right)$$
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