JEE MAIN - Mathematics Hindi (2021 - 27th August Evening Shift - No. 13)
यदि $$\mathop {\lim }\limits_{x \to \infty } \left( {\sqrt {{x^2} - x + 1} - ax} \right) = b$$ हो, तो जोड़ी (a, b) है :
$$\left( {1,{1 \over 2}} \right)$$
$$\left( {1, - {1 \over 2}} \right)$$
$$\left( { - 1,{1 \over 2}} \right)$$
$$\left( { - 1, - {1 \over 2}} \right)$$
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