JEE MAIN - Mathematics Hindi (2021 - 27th August Evening Shift - No. 11)

यदि $$y(x) = {\cot ^{ - 1}}\left( {{{\sqrt {1 + \sin x} + \sqrt {1 - \sin x} } \over {\sqrt {1 + \sin x} - \sqrt {1 - \sin x} }}} \right),x \in \left( {{\pi \over 2},\pi } \right)$$, तब $${{dy} \over {dx}}$$ at $$x = {{5\pi } \over 6}$$ है:
$$ - {1 \over 2}$$
$$-$$1
$${1 \over 2}$$
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