JEE MAIN - Mathematics Hindi (2021 - 26th February Morning Shift - No. 2)
$$\mathop {\lim }\limits_{h \to 0} 2\left\{ {{{\sqrt 3 \sin \left( {\frac{\pi}{6} + h} \right) - \cos \left( {\frac{\pi}{6} + h} \right)} \over {\sqrt 3 h\left( {\sqrt 3 \cosh - \sinh } \right)}}} \right\}$$ का मान है :
$$\frac{4}{3}$$
$$\frac{2}{3}$$
$$\frac{3}{4}$$
$$\frac{2}{\sqrt 3}$$
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