Sign In
JEE MAIN - Mathematics Hindi (2021 - 26th February Morning Shift - No. 12)
वक्र $$y = {1 \over 2}{x^4} - 5{x^3} + 18{x^2} - 19x$$ की अधिकतम ढाल बिंदु पर होती है :
$$\left( {3,{{21} \over 2}} \right)$$
(0, 0)
(2, 9)
(2, 2)
Comments (0)
Login To Comment
Advertisement
Allow javascript to properly load this page