JEE MAIN - Mathematics Hindi (2021 - 26th February Morning Shift - No. 11)
यदि $$\frac{{\sin^{-1}x}}{a} = \frac{{\cos^{-1}x}}{b} = \frac{{\tan^{-1}y}}{c}$$; $$0 < x < 1$$,
तो $$\cos \left(\frac{\pi c}{a + b}\right)$$ का मान है:
तो $$\cos \left(\frac{\pi c}{a + b}\right)$$ का मान है:
$$\frac{1 - y^2}{2y}$$
$$\frac{1 - y^2}{y\sqrt y}$$
$$1 - y^2$$
$$\frac{1 - y^2}{1 + y^2}$$
Comments (0)
