JEE MAIN - Mathematics Hindi (2021 - 26th August Evening Shift - No. 12)
यदि $${\left( {\sqrt 3 + i} \right)^{100}} = {2^{99}}(p + iq)$$, तो p और q इस समीकरण के मूल हैं :
$${x^2} - \left( {\sqrt 3 - 1} \right)x - \sqrt 3 = 0$$
$${x^2} + \left( {\sqrt 3 + 1} \right)x + \sqrt 3 = 0$$
$${x^2} + \left( {\sqrt 3 - 1} \right)x - \sqrt 3 = 0$$
$${x^2} - \left( {\sqrt 3 + 1} \right)x + \sqrt 3 = 0$$
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