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JEE MAIN - Mathematics Hindi (2021 - 25th July Morning Shift - No. 13)
समीकरण $${e^{6x}} - {e^{4x}} - 2{e^{3x}} - 12{e^{2x}} + {e^x} + 1 = 0$$ के वास्तविक मूलों की संख्या है:
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