JEE MAIN - Mathematics Hindi (2021 - 24th February Evening Shift - No. 15)

यदि $$\mathrm{a}+\alpha=1, \mathrm{~b}+\beta=2$$ तथा $$\mathrm{af}(\mathrm{x})+\alpha \mathrm{f}\left(\frac{1}{\mathrm{x}}\right)=\mathrm{bx}+\frac{\beta}{\mathrm{x}}, \mathrm{x} \neq 0$$ हैं, तो $$\frac{\mathrm{f}(\mathrm{x})+\mathrm{f}\left(\frac{1}{\mathrm{x}}\right)}{\mathrm{x}+\frac{1}{\mathrm{x}}}$$ बराबर है _____________.
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2

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