JEE MAIN - Mathematics Hindi (2021 - 20th July Evening Shift - No. 11)

यदि $$g(t) = \int_{ - \pi /2}^{\pi /2} {\cos \left( {{\pi \over 4}t + f(x)} \right)} dx$$, जहाँ $$f(x) = {\log _e}\left( {x + \sqrt {{x^2} + 1} } \right),x \in R$$। तो निम्नलिखित में से कौन सही है?
g(1) = g(0)
$$\sqrt 2 g(1) = g(0)$$
$$g(1) = \sqrt 2 g(0)$$
g(1) + g(0) = 0

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