JEE MAIN - Mathematics Hindi (2021 - 17th March Evening Shift - No. 9)
सीमा का मान
$$\mathop {\lim }\limits_{\theta \to 0} {{\tan (\pi {{\cos }^2}\theta )} \over {\sin (2\pi {{\sin }^2}\theta )}}$$ बराबर है :
$$\mathop {\lim }\limits_{\theta \to 0} {{\tan (\pi {{\cos }^2}\theta )} \over {\sin (2\pi {{\sin }^2}\theta )}}$$ बराबर है :
0
$$-$$$${1 \over 2}$$
$${1 \over 4}$$
$$-$$$${1 \over 4}$$
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