JEE MAIN - Mathematics Hindi (2021 - 16th March Morning Shift - No. 2)
यदि $${S_k} = \sum\limits_{r = 1}^k {{{\tan }^{ - 1}}\left( {{{{6^r}} \over {{2^{2r + 1}} + {3^{2r + 1}}}}} \right)} $$, तो $$\mathop {\lim }\limits_{k \to \infty } {S_k}$$ के बराबर है :
$${\cot ^{ - 1}}\left( {{3 \over 2}} \right)$$
$${\pi \over 2}$$
tan$$-$$1 (3)
$${\tan ^{ - 1}}\left( {{3 \over 2}} \right)$$
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