JEE MAIN - Mathematics Hindi (2020 - 9th January Morning Slot - No. 1)
यदि ƒ'(x) = tan–1(secx + tanx), $$ - {\pi \over 2} < x < {\pi \over 2}$$,
और ƒ(0) = 0, तो ƒ(1) का मान है :
और ƒ(0) = 0, तो ƒ(1) का मान है :
$${1 \over 4}$$
$${{\pi - 1} \over 4}$$
$${{\pi + 1} \over 4}$$
$${{\pi + 2} \over 4}$$
Comments (0)
