JEE MAIN - Mathematics Hindi (2020 - 9th January Evening Slot - No. 13)
यदि $$x = 2\sin \theta - \sin 2\theta $$ और $$y = 2\cos \theta - \cos 2\theta $$,
$$\theta \in \left[ {0,2\pi } \right]$$, तो $${{{d^2}y} \over {d{x^2}}}$$ पर $$\theta $$ = $$\pi $$ है :
$$\theta \in \left[ {0,2\pi } \right]$$, तो $${{{d^2}y} \over {d{x^2}}}$$ पर $$\theta $$ = $$\pi $$ है :
$${3 \over 8}$$
$${3 \over 2}$$
$${3 \over 4}$$
-$${3 \over 4}$$
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