JEE MAIN - Mathematics Hindi (2020 - 8th January Morning Slot - No. 3)
निम्न रेखाओं के बीच सबसे छोटी दूरी है
$${{x - 3} \over 3} = {{y - 8} \over { - 1}} = {{z - 3} \over 1}$$ और
$${{x + 3} \over { - 3}} = {{y + 7} \over 2} = {{z - 6} \over 4}$$ :
$${{x - 3} \over 3} = {{y - 8} \over { - 1}} = {{z - 3} \over 1}$$ और
$${{x + 3} \over { - 3}} = {{y + 7} \over 2} = {{z - 6} \over 4}$$ :
3
$${7 \over 2}\sqrt {30} $$
$$3\sqrt {30} $$
$$2\sqrt {30} $$
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