JEE MAIN - Mathematics Hindi (2020 - 8th January Evening Slot - No. 11)
यदि $$\alpha $$ और $$\beta $$ क्रमशः विस्तार के में x4 और x2 के गुणांक हों
$${\left( {x + \sqrt {{x^2} - 1} } \right)^6} + {\left( {x - \sqrt {{x^2} - 1} } \right)^6}$$, तब
$${\left( {x + \sqrt {{x^2} - 1} } \right)^6} + {\left( {x - \sqrt {{x^2} - 1} } \right)^6}$$, तब
$$\alpha + \beta = 60$$
$$\alpha - \beta = 60$$
$$\alpha + \beta = -30$$
$$\alpha - \beta = -132$$
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