JEE MAIN - Mathematics Hindi (2020 - 7th January Morning Slot - No. 15)
यदि g(x) = x2 + x - 1 और
(goƒ) (x) = 4x2 - 10x + 5, तो ƒ$$\left( {{5 \over 4}} \right)$$ के बराबर है:
(goƒ) (x) = 4x2 - 10x + 5, तो ƒ$$\left( {{5 \over 4}} \right)$$ के बराबर है:
$${1 \over 2}$$
$${3 \over 2}$$
-$${1 \over 2}$$
-$${3 \over 2}$$
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