JEE MAIN - Mathematics Hindi (2020 - 6th September Morning Slot - No. 12)

यदि $$\sum\limits_{i = 1}^n {\left( {{x_i} - a} \right)} = n$$ और $$\sum\limits_{i = 1}^n {{{\left( {{x_i} - a} \right)}^2}} = na$$
(n, a > 1) तब n
पर्यवेक्षणों x1 , x2 , ..., xn का मानक विचलन है :
$$a$$ – 1
$$n\sqrt {a - 1} $$
$$\sqrt {n\left( {a - 1} \right)} $$
$$\sqrt {a - 1} $$

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