JEE MAIN - Mathematics Hindi (2020 - 5th September Morning Slot - No. 1)
यदि $$\alpha $$ समीकरण , p(x) = x2 - x - 2 = 0, का सकारात्मक मूल है, तो
$$\mathop {\lim }\limits_{x \to {\alpha ^ + }} {{\sqrt {1 - \cos \left( {p\left( x \right)} \right)} } \over {x + \alpha - 4}}$$ का मान है :
$${1 \over \sqrt2}$$
$${1 \over 2}$$
$${3 \over \sqrt2}$$
$${3 \over 2}$$
Comments (0)
