JEE MAIN - Mathematics Hindi (2020 - 5th September Evening Slot - No. 11)

यदि L = sin2$$\left( \frac{\pi}{16} \right)$$ - sin2$$\left( \frac{\pi}{8} \right)$$ और
M = cos2$$\left( \frac{\pi}{16} \right)$$ - sin2$$\left( \frac{\pi}{8} \right)$$, तो :
L = $$ - \frac{1}{2\sqrt 2} + \frac{1}{2}\cos \frac{\pi}{8}$$
M = $$\frac{1}{2\sqrt 2} + \frac{1}{2}\cos \frac{\pi}{8}$$
M = $$\frac{1}{4\sqrt 2} + \frac{1}{4}\cos \frac{\pi}{8}$$
L = $$\frac{1}{4\sqrt 2} - \frac{1}{4}\cos \frac{\pi}{8}$$

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