JEE MAIN - Mathematics Hindi (2020 - 4th September Morning Slot - No. 13)
माना $$f\left( x \right) = \int {{{\sqrt x } \over {{{\left( {1 + x} \right)}^2}}}dx\left( {x \ge 0} \right)} $$. तो f(3) – f(1) का मान समान है :
$$ - {\pi \over {12}} + {1 \over 2} + {{\sqrt 3 } \over 4}$$
$$ {\pi \over {12}} + {1 \over 2} - {{\sqrt 3 } \over 4}$$
$$ - {\pi \over 6} + {1 \over 2} + {{\sqrt 3 } \over 4}$$
$${\pi \over 6} + {1 \over 2} - {{\sqrt 3 } \over 4}$$
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