JEE MAIN - Mathematics Hindi (2020 - 4th September Evening Slot - No. 6)

समाकलन
$$\int\limits_{{\pi \over 6}}^{{\pi \over 3}} {{{\tan }^3}x.{{\sin }^2}3x\left( {2{{\sec }^2}x.{{\sin }^2}3x + 3\tan x.\sin 6x} \right)dx} $$
के बराबर है:
$$ - {1 \over {9}}$$
$$ - {1 \over {18}}$$
$$ {7 \over {18}}$$
$${9 \over 2}$$

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