JEE MAIN - Mathematics Hindi (2019 - 9th April Morning Slot - No. 2)

यदि p, q $$ \in $$ R हों और 2 - $$\sqrt 3$$ द्विघात समीकरण, x2 + px + q = 0 का मूल हो, तब :
p2 – 4q – 12 = 0
q2 – 4p – 16 = 0
q2 + 4p + 14 = 0
p2 – 4q + 12 = 0

Comments (0)

Advertisement