JEE MAIN - Mathematics Hindi (2019 - 9th April Morning Slot - No. 11)

यदि कार्य ƒ, $$\left( {{\pi \over 6},{\pi \over 3}} \right)$$ के उपर परिभाषित है $$$f(x) = \left\{ {\matrix{ {{{\sqrt 2 {\mathop{\rm cosx}\nolimits} - 1} \over {\cot x - 1}},} & {x \ne {\pi \over 4}} \cr {k,} & {x = {\pi \over 4}} \cr } } \right.$$$ सतत है, तब k के बराबर है
1
1 / $$\sqrt 2$$
$${1 \over 2}$$
2

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