JEE MAIN - Mathematics Hindi (2019 - 9th April Evening Slot - No. 4)
यदि $$\cos x{{dy} \over {dx}} - y\sin x = 6x$$, (0 < x < $${\pi \over 2}$$)
और $$y\left( {{\pi \over 3}} \right)$$ = 0 तो $$y\left( {{\pi \over 6}} \right)$$ समान है :-
और $$y\left( {{\pi \over 3}} \right)$$ = 0 तो $$y\left( {{\pi \over 6}} \right)$$ समान है :-
$$ - {{{\pi ^2}} \over {2 }}$$
$$ - {{{\pi ^2}} \over {4\sqrt 3 }}$$
$$ {{{\pi ^2}} \over {2\sqrt 3 }}$$
$$ - {{{\pi ^2}} \over {2\sqrt 3 }}$$
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