JEE MAIN - Mathematics Hindi (2019 - 9th April Evening Slot - No. 10)
परिभाषा के डोमेन के लिए कार्य
$$f(x) = {1 \over {4 - {x^2}}} + {\log _{10}}({x^3} - x)$$ क्या है
$$f(x) = {1 \over {4 - {x^2}}} + {\log _{10}}({x^3} - x)$$ क्या है
(-1, 0) $$ \cup $$ (1, 2) $$ \cup $$ (2, $$\infty $$)
(-2, -1) $$ \cup $$ (-1,0) $$ \cup $$ (2, $$\infty $$)
(1, 2) $$ \cup $$ (2, $$\infty $$)
(-1, 0) $$ \cup $$ (1,2) $$ \cup $$ (3, $$\infty $$)
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