JEE MAIN - Mathematics Hindi (2019 - 9th April Evening Slot - No. 1)
इंटीग्रल $$\int\limits_0^1 {x{{\cot }^{ - 1}}(1 - {x^2} + {x^4})dx} $$ का मान है :-
$${\pi \over 2} - {1 \over 2}{\log _e}2$$
$${\pi \over 4} - {\log _e}2$$
$${\pi \over 4} - {1 \over 2}{\log _e}2$$
$${\pi \over 2} - {\log _e}2$$
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