JEE MAIN - Mathematics Hindi (2019 - 8th April Morning Slot - No. 7)
यदि $$f(x) = {\log _e}\left( {{{1 - x} \over {1 + x}}} \right)$$, $$\left| x \right| < 1$$ तब $$f\left( {{{2x} \over {1 + {x^2}}}} \right)$$ का मान है
2f(x2)
2f(x)
(f(x))2
-2f(x)
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