JEE MAIN - Mathematics Hindi (2019 - 8th April Morning Slot - No. 12)

$$\mathop {\lim }\limits_{x \to 0} {{{{\sin }^2}x} \over {\sqrt 2 - \sqrt {1 + \cos x} }}$$ के बराबर है:

$$ \sqrt 2$$

$$2 \sqrt 2$$

$$4 \sqrt 2$$