JEE MAIN - Mathematics Hindi (2019 - 8th April Morning Slot - No. 1)
यदि $$\alpha = {\cos ^{ - 1}}\left( {{3 \over 5}} \right)$$, $$\beta = {\tan ^{ - 1}}\left( {{1 \over 3}} \right)$$ जहाँ $$0 < \alpha ,\beta < {\pi \over 2}$$ हो, तो $$\alpha $$ - $$\beta $$ की मान होगी:
$${\tan ^{ - 1}}\left( {{9 \over {14 }}} \right)$$
$${\sin ^{ - 1}}\left( {{9 \over {5\sqrt {10} }}} \right)$$
$${\cos ^{ - 1}}\left( {{9 \over {5\sqrt {10} }}} \right)$$
$${\tan ^{ - 1}}\left( {{9 \over {5\sqrt {10} }}} \right)$$
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