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JEE MAIN - Mathematics Hindi (2019 - 12th April Evening Slot - No. 12)
$$\mathop {\lim }\limits_{x \to 0} {{x + 2\sin x} \over {\sqrt {{x^2} + 2\sin x + 1} - \sqrt {{{\sin }^2}x - x + 1} }}$$ है:
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