JEE MAIN - Mathematics Hindi (2019 - 11th January Evening Slot - No. 16)
डिफरेंशियल समीकरण का समाधान,
$${{dy} \over {dx}}$$ = (x – y)2, जब y(1) = 1, है :
$${{dy} \over {dx}}$$ = (x – y)2, जब y(1) = 1, है :
$$-$$ loge $$\left| {{{1 + x - y} \over {1 - x + y}}} \right|$$ = x + y $$-$$ 2
loge $$\left| {{{2 - x} \over {2 - y}}} \right|$$ = x $$-$$ y
loge $$\left| {{{2 - y} \over {2 - x}}} \right|$$ = 2(y $$-$$ 1)
$$-$$ loge $$\left| {{{1 - x + y} \over {1 + x - y}}} \right|$$ = 2(x $$-$$ 1)
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