JEE MAIN - Mathematics Hindi (2019 - 11th January Evening Slot - No. 12)
यदि $$\left| {\matrix{
{a - b - c} & {2a} & {2a} \cr
{2b} & {b - c - a} & {2b} \cr
{2c} & {2c} & {c - a - b} \cr
} } \right|$$
= (a + b + c) (x + a + b + c)2, x $$ \ne $$ 0,
तब x का मान है :
= (a + b + c) (x + a + b + c)2, x $$ \ne $$ 0,
तब x का मान है :
–2(a + b + c)
2(a + b + c)
abc
–(a + b + c)
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