JEE MAIN - Mathematics Hindi (2019 - 10th January Evening Slot - No. 14)
यदि $$\sum\limits_{r = 0}^{25} {\left\{ {{}^{50}{C_r}.{}^{50 - r}{C_{25 - r}}} \right\} = K\left( {^{50}{C_{25}}} \right)} ,\,\,$$ तब K का मान है :
224
225$$-$$ 1
225
(25)2
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