JEE MAIN - Mathematics Hindi (2019 - 10th April Morning Slot - No. 6)
यदि $$\alpha $$ और $$\beta $$ द्विघातीय समीकरण x2 + x sin $$\theta $$ - 2 sin $$\theta $$ = 0, $$\theta \in \left( {0,{\pi \over 2}} \right)$$ के मूल हैं, तो $${{{\alpha ^{12}} + {\beta ^{12}}} \over {\left( {{\alpha ^{ - 12}} + {\beta ^{ - 12}}} \right).{{\left( {\alpha - \beta } \right)}^{24}}}}$$ के बराबर है :
$${{{2^{12}}} \over {{{\left( {\sin \theta - 8} \right)}^6}}}$$
$${{{2^6}} \over {{{\left( {\sin \theta + 4} \right)}^{12}}}}$$
$${{{2^{12}}} \over {{{\left( {\sin \theta + 8} \right)}^{12}}}}$$
$${{{2^{12}}} \over {{{\left( {\sin \theta - 4} \right)}^{12}}}}$$
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