JEE MAIN - Mathematics Hindi (2019 - 10th April Morning Slot - No. 20)
यदि $$\mathop {\lim }\limits_{x \to 1} {{{x^4} - 1} \over {x - 1}} = \mathop {\lim }\limits_{x \to k} {{{x^3} - {k^3}} \over {{x^2} - {k^2}}}$$, तो k है :
$${3 \over 2}$$
$${8 \over 3}$$
$${4 \over 3}$$
$${3 \over 8}$$
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